Which of the following alternatives includes correct test values for x. based on equivalence partitioning?

The following 4 equivalence classes are given:

Which of the following alternatives includes correct test values for x. based on equivalence partitioning?
A . -100; 100:1000; 1001
B . -500; 0; 100; 1000
C . -99; 99:101; 1001
D . -1000; -100; 100; 1000

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Answer: D

Explanation:

The question is about selecting the correct test values for x based on equivalence partitioning.

Equivalence partitioning is a software test design technique that divides the input data of a software unit into partitions of equivalent data from which test cases can be derived.

In this case, the given equivalence classes are:

(x leq -100)

(-100 < x < 100)

(100 leq x < 1000)

(x geq 1000)

Option D provides a value from each of these partitions:

For (x leq -100), it gives -1000.

For (-100 < x < 100), it gives -100 and 100.

For (100 leq x < 1000), it gives 500.

For (x geq 1000), it gives 1500.

So, option D covers all four given equivalence classes with appropriate values.

Reference: ISTQB Certified Tester Foundation Level (CTFL) v4.0 documents available at ISTQB and ASTQB.

1: ISTQB Foundation Level Syllabus 2018, Version 4.0, p. 38

2: ISTQB Foundation Level Syllabus 2018, Version 4.0, p. 39

: ISTQB Foundation Level Syllabus 2018, Version 4.0, p. 40