What will be the output of the following code snippet?

What will be the output of the following code snippet?

d = {}

d[1] = 1

d[‘1’] = 2

d[1] += 1

sum = 0

for k in d:

sum += d[k]

print(sum)
A . 3
B. 4
C. 1
D. 2

View Answer

Answer: B

Explanation:

Topics: for dictionary indexes add and assign operator

Try it yourself:

d = {}

print(d) # {}

d[1] = 1

print(d) # {1: 1}

d[‘1’] = 2

print(d) # {1: 1, ‘1’: 2}

d[1] += 1

print(d) # {1: 2, ‘1’: 2}

sum = 0

for k in d:

sum += d[k]

print("key: ", k, " – value: ", d[k])

# key: 1 – value: 2

print(sum) # 4

sum = 0

for k in d.keys():

sum += d[k]

print("key: ", k, " – value: ", d[k])

# key: 1 – value: 2

print(sum) # 4

The knowledge you need here is that a dictionary

can have indexes of different data types.

Therefore d[1] is a different index than d[‘1’]

and they can both exist in the same dictionary.

To iterate through a dictionary is the same as

iterating through dict.keys()

In k will be the keys of the dictionary.

In this case 1 and ‘1’

The value of the first key will be 2

and the value of the other key will also be 2

and therefore (the) sum is 4