What is the expected output of the following code?

What is the expected output of the following code?

num = 1

def func():

num = num + 3

print(num)

func()

print(num)
A . 4 1
B. 4 4
C. The code is erroneous.
D. 1 4
E. 1 1

View Answer

Answer: C

Explanation:

Topics: def shadowing

Try it yourself:

num = 1

def func():

# num = num + 3  # UnboundLocalError: …

print(num)

func()

print(num)

print(‘———-‘)

num2 = 1

def func2():

x = num2 + 3

print(x) # 4

func2()

print(‘———-‘)

num3 = 1

def func3():

num3 = 3 # Shadows num3 from outer scope

print(num3) # 3

func3()

A variable name shadows into a function.

You can use it in an expression like in func2()

or you can assign a new value to it like in func3()

BUT you can not do both at the same time like in func()

There is going to be the new variable num

and you can not use it in an expression before its first assignment.