What is the difference in the noise floor perceived by a client using this bonded channel as compared to an unbonded 20MHz wide channel?

You are deploying a bonded 40 MHz wide channel.

What is the difference in the noise floor perceived by a client using this bonded channel as compared to an unbonded 20MHz wide channel?
A . 2dB
B . 3dB
C . 8dB
D . 4dB

View Answer

Answer: B

Explanation:

The difference in the noise floor perceived by a client using a bonded 40 MHz wide channel as compared to an unbonded 20 MHz wide channel is 3 dB. The noise floor is the level of background noise in a given frequency band. When two adjacent channels are bonded, the noise floor increases by 3 dB because the bandwidth is doubled and more noise is captured. The other options are incorrect because they do not reflect the correct relationship between bandwidth and noise floor.

References:

https://www.arubanetworks.com/techdocs/ArubaOS_86_Web_Help/Content/arubaos-solutions/wlan-rf/rf-fundam

https://www.arubanetworks.com/techdocs/ArubaOS_86_Web_Help/Content/arubaos-solutions/wlan-rf/channel-b