What code fragment codes the equivalent circuit if you remove the barrier in the following QuantumCircuit?
A . qc = QuantumCircuit(1,1)
qc.h(0)
qc.s(0)
qc.h(0)
qc.measure(0,0)
B . qc = QuantumCircuit(1,1)
qc.measure(0,0)
C . qc = QuantumCircuit(1,1)
qc.h(0)
qc.t(0)
qc.tdg(0)
qc.h(0)
qc.measure(0,0)
D . qc = QuantumCircuit(1,1)
qc.h(0)
qc.z(0)
qc.h(0)
qc.measure(0,0)
Answer: A
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