Juniper JN0-104 Junos, Associate (JNCIA-Junos) Online Training
Juniper JN0-104 Online Training
The questions for JN0-104 were last updated at Dec 24,2024.
- Exam Code: JN0-104
- Exam Name: Junos, Associate (JNCIA-Junos)
- Certification Provider: Juniper
- Latest update: Dec 24,2024
Click the Exhibit button.
You are attempting to capture traffic being sent to IP address 100.0.0.2, but are unable to see any packets.
Referring to the exhibit, what is the problem?
- A . You must use the dat 100.0.0.2 match condition instead of the src 100.0.0.2 match condition.
- B . You must add the size parameter to the command.
- C . Traffic destined for 100.0.0.2 is transit traffic.
- D . You must add the layer2-headers parameter to the command.
A
Explanation:
Questions and Answers PDF
Click the Exhibit button.
Click the Exhibit button.
What will happen when you commit the configuration shown in the exhibit?
- A . Gigabit interfaces on FPC 2 will inherit the family inet configuration.
- B . All gigabit interfaces will inherit the family inet configuration.
- C . VLAN 0 will be applied to gigabit interfaces on FPC 2.
- D . VLAN 0 will be applied to all gigabit interfaces.
13/97
Which output displays that the peer has been selected for NTP synchronization?
- A . Option A
- B . Option B
- C . Option C
- D . Option D
Click the Exhibit button
Referring to the exhibit, you are unable to see any traffic coming on interface ge-0/0/0.
What is causing this problem?
- A . The ge-0/0/0 interface is administratively down.
- B . The ge-0/0/0 interface has flow control disabled.
- C . The ge-0/0/0 interface’s physical link is down.
- D . The ge-0/0/0 interface has the link-mode set to half-duplex.
Click the Exhibit button.
Which two statements about the output shown in the exhibit are correct? (Choose two.)
- A . The neighbors are not using the Junos OS default OSPF priority value.
- B . The IP address assigned to the router’s ge-0/0/1.0 interface is 172.25.1.9.
- C . The router has two OSPF adjacencies.
- D . The router ID of the neighbor connected to the ge-0/0/1.0 interface is 192.168.100.3.
Click the Exhibit button.
Referring to the exhibit, which two statements are correct? (Choose two.)
- A . The last 5 second CPU utilization is 99%.
- B . The last 5 second CPU utilization is 1%.
- C . The control plane memory used is 63%.
- D . The data plane memory used is 63%.
Click the Exhibit button.
Referring to the exhibit, what happens when you filter the output of a command using the no-more parameter?
- A . The output is displayed in XML format.
- B . The output is displayed with no page breaks.
- C . The number of lines in the output are displayed.
- D . The last screen of information is displayed.
B
Explanation:
Ref: | (pipe) | Junos OS | Juniper Networks
“| (pipe)
…
Description
Filter the output of an operational mode or a configuration mode command.
…
Options
…
no-more Display output all at once rather than one screen at a time.
…”
Which two routing policy actions are considered policy flow control actions in the Junos OS? (Choose two.)
- A . accept
- B . next hop
- C . next policy
- D . next term
AB
Explanation:
https://www.juniper.net/documentation/us/en/software/junos/routing-policy/topics/concept/policy-configuring-actions-in-routing-policy-terms.html
In the show I compare rollback 49 command, what is the purpose of the I?
- A . The | is a shortcut to redirect output from a command line to a file.
- B . The filters the output of the show command.
- C . The | is used to represent an "either or” statement.
- D . The | changes the command from an operational command to a configuration mode command.
B
Explanation:
ttps://www.juniper.net/documentation/us/en/software/junos/cli/topics/ref/command/pipe.html
What is the network address for a host with an IP address of 192.168.87.125/16?
- A . 192.168.128.0
- B . 192.168.0.0
- C . 192.168.96.0
- D . 192.168.87.0
B
Explanation:
The network address for a host is determined by performing a bitwise AND operation between the host’s IP address and the subnet mask. In this case, the IP address is 192.168.87.125 and the subnet mask is 255.255.0.0 (or /16), which means that the first 16 bits are used for the network portion of the address and the remaining 16 bits are used for the host portion.
To find the network address, we perform the bitwise AND operation:
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