If the expression 
, then one possible value of x could be:
A . C 1
B . C 2
C . C 5
D . 1
E . 2
Answer: A
Explanation:
Cross multiply and solve for x:
3 × 2x = ( 2 + x) × (x C 5)
6x = x 2 C 3x C 10
x 2 C 9x C 10 = 0
(x C 10) × (x + 1)
x = 10, x = C1
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