You have a view.
How will you list all the object references of the view?
A . GET_OBJECT_REFERENCES
B. GET_VIEW_REFERENCES
C. GET_VIEW_METADATA
Answer: A
Explanation:
GET_OBJECT_REFERENCES
Returns a list of objects that a specified object references. Input is currently limited to the name of a
view.
https://docs.snowflake.com/en/sql-reference/functions/get_object_references.html#get-object-references
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Please do the below hands-on to understand this concept create or replace database ex1_gor_x; use database ex1_gor_x;
use schema public;
— create a set of tables
create or replace table x_tab_a (mycol int not null);
create or replace table x_tab_b (mycol int not null);
create or replace table x_tab_c (mycol int not null);
— create views with increasing complexity of references create or replace view x_view_d as
select * from x_tab_a join x_tab_b
using ( mycol );
create or replace view x_view_e as select x_tab_b.* from x_tab_b, x_tab_c where x_tab_b.mycol=x_tab_c.mycol; –create a second database
create or replace database ex1_gor_y; use database ex1_gor_y;
use schema public;
— create a table in the second database
create or replace table y_tab_a (mycol int not null);
— create more views with increasing levels of references create or replace view y_view_b as
select * from ex1_gor_x.public.x_tab_a
join y_tab_a
using ( mycol );
create or replace view y_view_c as
select b.* from ex1_gor_x.public.x_tab_b b, ex1_gor_x.public.x_tab_c c where b.mycol=c.mycol;
create or replace view y_view_d as
select * from ex1_gor_x.public.x_view_e;
create or replace view y_view_e as
select e.* from ex1_gor_x.public.x_view_e e, y_tab_a where e.mycol=y_tab_a.mycol; create or replace view y_view_f as
select e.* from ex1_gor_x.public.x_view_e e, ex1_gor_x.public.x_tab_c c, y_tab_a
where e.mycol=y_tab_a.mycol
and e.mycol=c.mycol;
— retrieve the references for the last view created
select * from table(get_object_references(database_name=>’ex1_gor_y’, schema_name=>’public’, object_name=>’y_view_f’));
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