How should this expression be modified to ensure that evaluates to false?

JavaScript Developer I 1 Comment

Refer to the expression below:

Let x = (‘1’ + 2) == (6 * 2);

How should this expression be modified to ensure that evaluates to false?
A . Let x = (‘1’ + ‘ 2’) == ( 6 * 2);
B . Let x = (‘1’ + 2) == ( 6 * 2);
C . Let x = (1 + 2) == ( ‘6’ / 2);
D . Let x = (1 + 2 ) == ( 6 / 2);

Answer: B

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Sree Charan Shatdarsanam
Sree Charan Shatdarsanam
2 years ago

There is no change in B and original question., both still return true,

Is B supposed to have three “=” ? i.e.
let x = (‘1’ + 2) === ( 6 * 2); ??

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