Assuming that the speakers in the picture on the LEFT are 8 Q drivers, what is the impedance of the speaker system on the left?

Assuming that the speakers in the picture on the LEFT are 8 Q drivers, what is the impedance of the speaker system on the left?

A . 2Q
B . 4Q
C . 8Q
D . 16 Q

View Answer

Answer: A

Explanation:

Assuming the speakers on the left are 8Ω drivers and they are connected in parallel, the total impedance ZtZ_tZt can be calculated using the formula for parallel resistance:

Zt 1=Z1 1+Z2 1

For two 8Ω speakers in parallel:

1Zt=18+18=28=14frac{1}{Z_t} = frac{1}{8} + frac{1}{8} = frac{2}{8} = frac{1}{4}Zt​1​=81​+81​=82​=41​ Therefore,

Zt=4ΩZ_t = 4ΩZt=4Ω

If the wiring in the diagram shows two pairs of 8Ω speakers connected in parallel, the total impedance is 4Ω for each pair, and if these pairs are then connected in parallel again, the final impedance is:

1Zt=14+14=24=12frac{1}{Z_t} = frac{1}{4} + frac{1}{4} = frac{2}{4} = frac{1}{2}Zt 1 =41 +41 =42 =21

Thus, the total impedance is 2Ω.

Reference: Axis Communications – Audio System Design

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