What code fragment codes the equivalent circuit if you remove the barrier in the following QuantumCircuit?

What code fragment codes the equivalent circuit if you remove the barrier in the following QuantumCircuit?

A . qc = QuantumCircuit(1,1)
qc.h(0)
qc.s(0)
qc.h(0)
qc.measure(0,0)

B . qc = QuantumCircuit(1,1)
qc.measure(0,0)
C . qc = QuantumCircuit(1,1)
qc.h(0)
qc.t(0)
qc.tdg(0)
qc.h(0)
qc.measure(0,0)
D . qc = QuantumCircuit(1,1)
qc.h(0)
qc.z(0)
qc.h(0)
qc.measure(0,0)

Answer: A

Subscribe
Notify of
guest
0 Comments
Inline Feedbacks
View all comments